Calculate the maximum acceleration of a moving car so that a body lying on the floor of the car remains stationary. The coefficient of static friction between the body and the floor is 0.15 (ms) [2023]

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

More

Solution

Q.
Calculate the maximum acceleration of a moving car so that a body lying on the floor of the car remains stationary. The coefficient of static friction between the body and the floor is 0.15 ( $g = 10 {ms}^{- 2}$ ) [2023]

1 $1.5 {ms}^{- 2}$

2 $50 {ms}^{- 2}$

3 $1.2 {ms}^{- 2}$

4 $150 {ms}^{- 2}$

Ans.
(1)

Let $μ$ be the coefficient of friction between the car and the road.

As, retarding force = force of friction

$∴$ $m a = μ m g \Rightarrow a = μ \times g$

Putting the given values, we get

$a = (0.15) (10 {ms}^{- 2}) = 1.5 {ms}^{- 2}$

Want Us to Email you About Special Offers & Updates?