Bond enthalpies of H2, X2 and HX are in the ratio 2 : 1 : 2, if enthalpy of formation of HX is -50 kJ mol-1, the bond enthalpy of X2 is
(1)
12H2+12X2→HX ΔH=-50
2a a 2a
2a2+a2-2a=-50
3a-4a=-100
a=100