At t=0, a body of mass 100 g starts moving under the influence of a force (5i^+10j^) N. After 2 s its position is (2xi^+5yj^) m. The ratio x:y is _______. [2026]
(4)
a→=F→m=5i^+10j^0.1=(50i^+100j^)
s→=u→t+12a→t2
s→=0+12[50i^+100j^](2)2
s→=100i^+200j^=r→=2xi^+5yj^
2x=100⇒x=50 and 5y=200⇒y=40
⇒xy=54