As shown in the figure, two parallel plate capacitors having equal plate area of are joined in such a way that . The equivalent capacitance of the combination is . The value of is ___________ . [2023]

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Solution

Q.
As shown in the figure, two parallel plate capacitors having equal plate area of $200 {cm}^{2}$ are joined in such a way that $a \neq b$ . The equivalent capacitance of the combination is $x ε_{0} F$ . The value of $x$ is ___________ . [2023]

Ans.
(5)

$C = \frac{ε_{0} A}{(d - c)} = \frac{ε_{0} \times 200 \times 10^{- 4}}{4 \times 10^{- 3}}$

$∴$ $x = 5$

$The situation is equivalent to a conducting slab placed between the plates.$

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