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Solution


Q.

As per the given figure, a small ball P slides down the quadrant of a circle and hits the other ball Q of equal mass which is initially at rest. Neglecting the effect of friction and assume the collision to be elastic, the velocity of ball Q after collision will be (g = 10 m/s2)        [2023]
1 0  
2 0.25 m/s  
3 2 m/s  
4 4 m/s  

Ans.

(3)

The velocities will be interchanged after collision. Speed of P just before collision =2gh

=2×10×0.2

=2 m/s