Aqueous HCl reacts with . What is the weight (in g) of liberated when 8.7 g of is reacted with excess aqueous HCl solution ? (Given Molar mass in g Mn = 55, Cl

Question

Aqueous HCl reacts with ${MnO}_{2} {(s) to form MnCl}_{2} {(aq), Cl}_{2} (g) and H₂O (l)$ . What is the weight (in g) of ${Cl}_{2}$ liberated when 8.7 g of ${MnO}_{2} (s)$ is reacted with excess aqueous HCl solution

(Given Molar mass in g ${mol}^{- 1}$ Mn = 55, Cl = 35.5, O = 16, H = 1) [2026]

Smart Achievers · Accepted Answer

(3)

${MnO}_{2} + 4 HCl \to {MnCl}_{2} + {Cl}_{2} + 2 H_{2} O$

$\frac{8.7}{87}$ Excess

$= 0.1 mole$ $0.1 mole$

$Wt. of C l_{2} obtained = 0.1 \times 71 = 7.1 g$

Solution

Q.
Aqueous HCl reacts with ${MnO}_{2} {(s) to form MnCl}_{2} {(aq), Cl}_{2} (g) and H₂O (l)$ . What is the weight (in g) of ${Cl}_{2}$ liberated when 8.7 g of ${MnO}_{2} (s)$ is reacted with excess aqueous HCl solution

(Given Molar mass in g ${mol}^{- 1}$ Mn = 55, Cl = 35.5, O = 16, H = 1) [2026]

1 14.2

2 71

3 7.1

4 21.3

Ans.
(3)

${MnO}_{2} + 4 HCl \to {MnCl}_{2} + {Cl}_{2} + 2 H_{2} O$

$\frac{8.7}{87}$ Excess

$= 0.1 mole$ $0.1 mole$

$Wt. of C l_{2} obtained = 0.1 \times 71 = 7.1 g$

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