An object is projected with kinetic energy K from a point A at an angle 60° with the horizontal. [2026]

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

More

Solution

Q.
An object is projected with kinetic energy K from a point A at an angle 60° with the horizontal. The ratio of the difference in kinetic energies at points B and C to that at point A (see figure), in the absence of air friction, is: [2026]

1 1 : 4

2 2 : 3

3 3 : 4

4 1 : 2

Ans.
(3)

${(K E)}_{A} = K = \frac{1}{2} m u^{2}$

${(K E)}_{B} = \frac{K}{4} = \frac{1}{2} m {(\frac{u}{2})}^{2} = \frac{K}{4} (u_{B} = u \cos 60 ° = \frac{u}{2})$

${(K E)}_{C} = K$

$Ratio = \frac{K - K / 4}{K}$

$= \frac{3 K / 4}{K} = \frac{3}{4}$

Want Us to Email you About Special Offers & Updates?