An iron rod of susceptibility 599 is subjected to a magnetising field of . The permeability of the material of the rod is [2020]

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Q.
An iron rod of susceptibility 599 is subjected to a magnetising field of $1200$ $A$ $m^{- 1}$ . The permeability of the material of the rod is $(μ_{0} = 4 π \times 10^{- 7}$ $T m A^{- 1})$ [2020]

1 $2.4 π \times 10^{- 4}$ $T m A^{- 1}$

2 $8.0 \times 10^{- 5}$ $T m A^{- 1}$

3 $2.4 π \times 10^{- 5}$ $T m A^{- 1}$

4 $2.4 π \times 10^{- 7}$ $T m A^{- 1}$

Ans.
(1)

Given, $X_{m} = 599$

Relative permeability of the material, $μ_{r} = 1 + X_{m}$

or $μ_{r} = 1 + 599 = 600$

$∴$ $μ = μ_{r} μ_{0} = 600 \times (4 π \times 10^{- 7})$

$= 2.4 π \times 10^{- 4} T$ $m$ $A^{- 1}$

Solution

Q.
An iron rod of susceptibility 599 is subjected to a magnetising field of $1200$ $A$ $m^{- 1}$ . The permeability of the material of the rod is $(μ_{0} = 4 π \times 10^{- 7}$ $T m A^{- 1})$ [2020]

1 $2.4 π \times 10^{- 4}$ $T m A^{- 1}$

2 $8.0 \times 10^{- 5}$ $T m A^{- 1}$

3 $2.4 π \times 10^{- 5}$ $T m A^{- 1}$

4 $2.4 π \times 10^{- 7}$ $T m A^{- 1}$

Ans.
(1)

Given, $X_{m} = 599$

Relative permeability of the material, $μ_{r} = 1 + X_{m}$

or $μ_{r} = 1 + 599 = 600$

$∴$ $μ = μ_{r} μ_{0} = 600 \times (4 π \times 10^{- 7})$

$= 2.4 π \times 10^{- 4} T$ $m$ $A^{- 1}$

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Solution

Q. An iron rod of susceptibility 599 is subjected to a magnetising field of 1200 A m-1. The permeability of the material of the rod is (μ0=4π×10-7T m A-1) [2020]

1 2.4π×10-4T m A-1

2 8.0×10-5T m A-1

3 2.4π×10-5T m A-1

4 2.4π×10-7T m A-1

Ans. (1) Given, Xm=599 Relative permeability of the material, μr=1+Xm or μr=1+599=600 ∴ μ=μrμ0=600×(4π×10-7) =2.4π×10-4T m A-1

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Q.
An iron rod of susceptibility 599 is subjected to a magnetising field of $1200$ $A$ $m^{- 1}$ . The permeability of the material of the rod is $(μ_{0} = 4 π \times 10^{- 7}$ $T m A^{- 1})$ [2020]

1 $2.4 π \times 10^{- 4}$ $T m A^{- 1}$

2 $8.0 \times 10^{- 5}$ $T m A^{- 1}$

3 $2.4 π \times 10^{- 5}$ $T m A^{- 1}$

4 $2.4 π \times 10^{- 7}$ $T m A^{- 1}$

Ans.
(1)

Given, $X_{m} = 599$

Relative permeability of the material, $μ_{r} = 1 + X_{m}$

or $μ_{r} = 1 + 599 = 600$

$∴$ $μ = μ_{r} μ_{0} = 600 \times (4 π \times 10^{- 7})$

$= 2.4 π \times 10^{- 4} T$ $m$ $A^{- 1}$