An infinite wire has a circular bend of radius a, and carrying a current as shown in figure. The magnitude of magnetic field at the origin O of the arc is given by: [2025]

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Q.

An infinite wire has a circular bend of radius a, and carrying a current $I$ as shown in figure.

The magnitude of magnetic field at the origin O of the arc is given by: [2025]

1 $\frac{μ_{0}}{4 π} \frac{I}{a} [\frac{π}{2} + 1]$

2 $\frac{μ_{0}}{4 π} \frac{I}{a} [\frac{3 π}{2} + 1]$

3 $\frac{μ_{0}}{2 π} \frac{I}{a} [\frac{π}{2} + 2]$

4 $\frac{μ_{0}}{4 π} \frac{I}{a} [\frac{3 π}{2} + 2]$

Ans.
(2)

$B_{1} = \frac{μ_{0} I}{4 π a} \otimes$

$B_{2} = \frac{μ_{0}}{4 π} \frac{I}{a} (\frac{3 π}{2}) \otimes$

$B_{3} = 0$

$B = \frac{μ_{0}}{4 π} \frac{I}{a} (1 + \frac{3 π}{2}) \otimes$

Solution

Q.

An infinite wire has a circular bend of radius a, and carrying a current $I$ as shown in figure.

The magnitude of magnetic field at the origin O of the arc is given by: [2025]

1 $\frac{μ_{0}}{4 π} \frac{I}{a} [\frac{π}{2} + 1]$

2 $\frac{μ_{0}}{4 π} \frac{I}{a} [\frac{3 π}{2} + 1]$

3 $\frac{μ_{0}}{2 π} \frac{I}{a} [\frac{π}{2} + 2]$

4 $\frac{μ_{0}}{4 π} \frac{I}{a} [\frac{3 π}{2} + 2]$

Ans.
(2)

$B_{1} = \frac{μ_{0} I}{4 π a} \otimes$

$B_{2} = \frac{μ_{0}}{4 π} \frac{I}{a} (\frac{3 π}{2}) \otimes$

$B_{3} = 0$

$B = \frac{μ_{0}}{4 π} \frac{I}{a} (1 + \frac{3 π}{2}) \otimes$

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Solution

Q. An infinite wire has a circular bend of radius a, and carrying a current I as shown in figure. The magnitude of magnetic field at the origin O of the arc is given by: [2025]

1 μ04πIa[π2+1]

2 μ04πIa[3π2+1]

3 μ02πIa[π2+2]

4 μ04πIa[3π2+2]

Ans. (2) B1=μ0I4πa⊗ B2=μ04πIa(3π2)⊗ B3=0 B=μ04πIa(1+3π2)⊗

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Q.

An infinite wire has a circular bend of radius a, and carrying a current $I$ as shown in figure.

The magnitude of magnetic field at the origin O of the arc is given by: [2025]

1 $\frac{μ_{0}}{4 π} \frac{I}{a} [\frac{π}{2} + 1]$

2 $\frac{μ_{0}}{4 π} \frac{I}{a} [\frac{3 π}{2} + 1]$

3 $\frac{μ_{0}}{2 π} \frac{I}{a} [\frac{π}{2} + 2]$

4 $\frac{μ_{0}}{4 π} \frac{I}{a} [\frac{3 π}{2} + 2]$

Ans.
(2)

$B_{1} = \frac{μ_{0} I}{4 π a} \otimes$

$B_{2} = \frac{μ_{0}}{4 π} \frac{I}{a} (\frac{3 π}{2}) \otimes$

$B_{3} = 0$

$B = \frac{μ_{0}}{4 π} \frac{I}{a} (1 + \frac{3 π}{2}) \otimes$