An electron in a hydrogen atom revolves around its nucleus with a speed of in an orbit of radius . The magnetic field produced at the nucleus of the hydrogen atom is _________ T. [2023]

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Solution

Q.
An electron in a hydrogen atom revolves around its nucleus with a speed of $6.76 \times 10^{6} {ms}^{- 1}$ in an orbit of radius $0.52 Å$ . The magnetic field produced at the nucleus of the hydrogen atom is _________ T. [2023]

Ans.
(40)

$Magnetic field due to moving charge$

$B = \frac{μ_{0}}{4 π} \frac{q v \sin θ}{r^{2}}$

$B = \frac{μ_{0}}{4 π} \frac{e v \sin (π / 2)}{r^{2}}$

$B = \frac{10^{- 7} \times 1.6 \times 10^{- 19} \times 6.76 \times 10^{6}}{0.52 \times 0.52 \times 10^{- 20}}$

$\Rightarrow B = 40 T$

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