An electric field is given by The electric flux through a surface area lying in YZ-plane (in SI unit) is

Question

An electric field is given by $(6 \hat{i} + 5 \hat{j} + 3 \hat{k}) N / C .$ The electric flux through a surface area $30 \hat{i}$ $m^{2}$ lying in YZ-plane (in SI unit) is [2024]

Smart Achievers · Accepted Answer

(1)

$\vec{E} = (6 \hat{i} + 5 \hat{j} + 3 \hat{k}) N / C$

$\vec{A} = 30 \hat{i}$ $m^{2}$

Electric flux, $ϕ = \vec{E} \cdot \vec{A}$

$ϕ = (6 \hat{i} + 5 \hat{j} + 3 \hat{k}) \cdot (30 \hat{i}) = 180 \frac{N m^{2}}{C}$

Solution

Q.
An electric field is given by $(6 \hat{i} + 5 \hat{j} + 3 \hat{k}) N / C .$ The electric flux through a surface area $30 \hat{i}$ $m^{2}$ lying in YZ-plane (in SI unit) is [2024]

1 180

2 90

3 150

4 60

Ans.
(1)

   $\vec{E} = (6 \hat{i} + 5 \hat{j} + 3 \hat{k}) N / C$

$\vec{A} = 30 \hat{i}$ $m^{2}$

  Electric flux, $ϕ = \vec{E} \cdot \vec{A}$

   $ϕ = (6 \hat{i} + 5 \hat{j} + 3 \hat{k}) \cdot (30 \hat{i}) = 180 \frac{N m^{2}}{C}$

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