Q.

An aircraft executes a horizontal loop at a speed of 720 km h-1 with its wings banked at 15°. What is the radius of the loop

(Take g = 10 m s-2, tan 15° = 0.27)

1 14.8 km  
2 14.8 m  
3 29.6 km  
4 29.6 m  

Ans.

(1)

Here,  v=720 km h-1=720×518 m s-1=200 m s-1

θ=15°,  g=10 m s-2;  As tanθ=v2rg

∴  r=v2tanθg=(200 m s-1)2tan15°×10 m s-2=14815 m=14.8 km