A wire of density is stretched between two clamps 0.5 m apart. The extension developed in the wire is . If , the fundamental frequency of vibration in the wire will be ________ Hz. [2023]

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Solution

Q.
A wire of density $8 \times 10^{3} {kg/m}^{3}$ is stretched between two clamps 0.5 m apart. The extension developed in the wire is $3.2 \times 10^{- 4} m$ . If $Y = 8 \times 10^{10} {N/m}^{2}$ , the fundamental frequency of vibration in the wire will be ________ Hz. [2023]

Ans.
(80)

$f = \frac{1}{2 L} \sqrt{\frac{T}{μ}} = \frac{1}{2 L} \sqrt{\frac{Y A Δ L}{ρ A L}}$

$f = 80 Hz$

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