A value of b for which the equations
x2+bx-1=0
x2+x+b=0
have one root in common is [2011]
(2)
Let α be the common root of given equations, then
α2+bα-1=0 ...(i)
and α2+α+b=0 ...(ii)
On subtracting (ii) from (i), we get
(b-1)α-(b+1)=0
⇒α=b+1b-1
Substituting this value of α in equation (i), we get
(b+1b-1)2+b(b+1b-1)-1=0
⇒b3+3b=0
⇒b=0, i3, -i3