Q.

A value of b for which the equations

x2+bx-1=0

x2+x+b=0

have one root in common is                          [2011]

1 -2  
2 -i3  
3 i5  
4 2  

Ans.

(2)

Let α be the common root of given equations, then

α2+bα-1=0               ...(i)

and  α2+α+b=0             ...(ii)

On subtracting (ii) from (i), we get

(b-1)α-(b+1)=0

α=b+1b-1

Substituting this value of α in equation (i), we get

(b+1b-1)2+b(b+1b-1)-1=0

b3+3b=0

b=0, i3, -i3