• 072920 77839
  • info@smartachievers.in
Menu
Back
  • JEE ADVANCE
  • JEE MAIN
  • NEET
  • BITSAT
  • CBSE BOARD
  • UP BOARD
  • CUET
JEE ADVANCE
  • CLASS XI - XII
  • CRASH COURSE
CRASH COURSE
JEE MAIN
  • CLASS XI - XII
  • CRASH COURSE
CRASH COURSE
NEET
  • CLASS XI - XII
  • CRASH COURSE
BITSAT
  • CLASS XI - XII
CBSE BOARD
  • CLASS IX
  • CLASS X
  • CLASS XI
  • CLASS XII
  • CLASS VI
  • CLASS VII
  • CLASS VIII
UP BOARD
  • CLASS IX
  • CLASS X
  • CLASS XI
  • CLASS XII
CUET
  • CRASH COURSE
Courses


Solution


Q.

Read the passage given below and answer the following questions from (i) to (v).

A magnet must exert an equal and opposite force on a current-carrying conductor. We know that current is due to the charge in motion. Thus, it is evident that a charge moving in a magnetic field experiences a force. If the direction of motion is perpendicular to the direction of the magnetic field, the magnitude of force experienced depends upon the charge, velocity, and strength of the magnetic field. Fleming’s left-hand rule gives the direction of the magnetic force.

(iii) A uniform magnetic field exists from left to right on a surface. An electron and proton moving in the directions as shown in the figure will experience:
1 Forces both pointing into the plane of the surface.  
2 Forces both pointing out of the plane of the surface.  
3 The electron will experience into the plane and proton out of the plane.  
4 The electron will experience opposite to and proton along the direction of the uniform magnetic field.  

Ans.

(1)