Q.

A train S1, moving with a uniform velocity of 108 km/h approaches another train S2 standing on a platform. An observer O moves with a uniform velocity of 36 km/h towards S2 as shown in figure. Both the trains are blowing whistles of same frequency 120 Hz. When O is 600 m away from S2 and distance between S1 and S2 is 800 m, the number of beats heard by O is _____

[Speed of the sound = 330 m/s]                    [2019]


Ans.

(8.13)

 Apparent frequency heard by observer due to source S1

ν1=ν[v+v0v]=120[330+10330]=120×3433=123.636 Hz

Apparent frequency heard by observer due to source S2

ν2=ν[v+v0v-vs]=120[330+10cos53°330-30cos37°]

  ν2=120[330+10×0.6330-30×0.8]=120[336306]=131.764 Hz

  Beat frequency, νb=ν2-ν1=131.764-123.636=8.125 Hz8.13 Hz