Q.

A student has been given a compound “x” of molecular formula– C6H7N. ‘x’ is sparingly soluble in water. However, on addition of dilute mineral acid, ‘x’ becomes soluble in water. ‘x’ when treated with CHCl3 and KOH(alc). ‘y’ is produced. ‘y’ has a specific unpleasant smell. On treatment with benzenesulphonyl chloride, ‘x’ gives a compound ‘z’ which is soluble in alkali. The number of different “H” atoms present in ‘z’ is:   [2026]

1 7  
2 8  
3 5  
4 4  

Ans.

(1)