A stone of mass 5 kg is tied to a string of length 10 m and is whirled round in a horizontal circle. What is the maximum speed with which the stone can be whirled around if the string can withstand a maximum tension of 200 N?

Question

Smart Achievers · Accepted Answer

(3)

Here, $m = 5 kg, r = 10 m, T_{\max} = 200 N$

As $T_{\max} = \frac{m v_{\max}^{2}}{r}$

$∴$ $v_{\max}^{2} = \frac{T_{\max} \times r}{m}$

$∴$ $v_{\max}^{2} = \frac{200 \times 10}{5} = 400$

$\Rightarrow$ $v_{\max} = 20 {m s}^{- 1}$

Solution

Q.
A stone of mass 5 kg is tied to a string of length 10 m and is whirled round in a horizontal circle. What is the maximum speed with which the stone can be whirled around if the string can withstand a maximum tension of 200 N

1 10 $m s^{- 1}$

2 15 $m s^{- 1}$

3 20 $m s^{- 1}$

4 25 $m s^{- 1}$

Ans.
(3)

Here, $m = 5 kg, r = 10 m, T_{\max} = 200 N$

As $T_{\max} = \frac{m v_{\max}^{2}}{r}$

$∴$ $v_{\max}^{2} = \frac{T_{\max} \times r}{m}$

$∴$ $v_{\max}^{2} = \frac{200 \times 10}{5} = 400$

$\Rightarrow$ $v_{\max} = 20 {m s}^{- 1}$

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Solution

Q. A stone of mass 5 kg is tied to a string of length 10 m and is whirled round in a horizontal circle. What is the maximum speed with which the stone can be whirled around if the string can withstand a maximum tension of 200 N

1 10 m s-1

2 15 m s-1

3 20 m s-1

4 25 m s-1

Ans. (3) Here, m=5 kg, r=10 m, Tmax=200 N As Tmax=mvmax2r ∴ vmax2=Tmax×rm ∴ vmax2=200×105=400 ⇒ vmax=20 m s-1