A square frame of side 10 cm and a long straight wire carrying current 1 A are in the plane of the paper. Starting from close to the wire, the frame moves towards the right with a constant speed of $10 {ms}^{- 1}$ (see figure). [2020]

The e.m.f. induced at the time the left arm of the frame is at $x = 10 cm$ from the wire is:

Question

A square frame of side 10 cm and a long straight wire carrying current 1 A are in the plane of the paper. Starting from close to the wire, the frame moves towards the right with a constant speed of $10 {ms}^{- 1}$ (see figure). [2020]

The e.m.f. induced at the time the left arm of the frame is at $x = 10 cm$ from the wire is:

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(2)

In the given question,

Current flowing through the wire, $I = 1 A$

Speed of the frame, $v = 10 {ms}^{- 1}$

Side of square loop, $l = 10 cm$

Distance of square frame from current carrying wire, $x = 10 cm$

We have to find, e.m.f. induced $e = ?$

According to Biot-Savart's law,

$B = \frac{μ_{0} I d l \sin θ}{4 π x^{2}} = \frac{4 π \times 10^{- 7}}{4 π} \times \frac{1 \times 10^{- 1}}{{(10^{- 1})}^{2}} = 10^{- 6}$

Induced e.m.f., $e = B l v = 10^{- 6} \times 10^{- 1} \times 10 = 1 μ V$

Solution

1 $2 μ V$

2 $1 μ V$

3 $0.75 μ V$

4 $0.5 μ V$

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Solution

1 2 μV

2 1 μV

3 0.75 μV

4 0.5 μV

Want Us to Email you About Special Offers & Updates?

1 $2 μ V$

2 $1 μ V$

3 $0.75 μ V$

4 $0.5 μ V$