Q.

A solid sphere of radius R has a charge Q distributed in its volume with a charge density ρ=kra, where k and a are constants and r is the distance from its centre. If the electric field at r=R2 is 18 times that at r=R, find the value of a.                  [2009]


Ans.

(2)

Let there be a spherical shell of radius x and thickness dx. Volume of this shell, V=4πx2(dx). Charge enclosed in this shell

dq=(4πx2)dx×kxa

or,  dq=4πkx2+adx

For r=R:

Total charge enclosed in the sphere of radius R

Q=0R4πkx2+adx=4πkR3+a3+a

  Electric field at r=R

E1=14πε0·4πkR3+a(3+a)R2=14πε0·4πk3+aR1+a

For r=R2:

Total charge enclosed in the sphere of radius R2

Q'=0R/24πkx2+adx=4πk(R/2)3+a3+a

  The electric field at r=R2

E2=14πε0·4πk3+a(R/2)3+a(R/2)2=14πε0·4πk3+a(R2)1+a

  E2=18E1

  14πε0·4πk3+a(R2)1+a=123×14πε0·4πk3+aR1+a

  1+a=3

  a=2