Q.

A small block of mass of 0.1 kg lies on a fixed inclined plane PQ which makes an angle θ with the horizontal. A horizontal force of 1 N acts on the block through its centre of mass as shown in the figure.   

                          

The block remains stationary if (take g=10 m/s2)           [2012]

1 θ=45°  
2 θ>45° and a frictional force acts on the block towards P  
3 θ>45° and a frictional force acts on the block towards Q  
4 θ<45° and a frictional force acts on the block towards Q  

Ans.

(1, 3)

The various forces acting on the block are as shown in the figure.

When θ=45°, sinθ=cosθ

The block will remain stationary and the frictional force is zero.

When θ>45°, sinθ>cosθ

Therefore a frictional force acts towards Q.

When θ<45°, cosθ>sinθ.

Therefore a frictional force acts towards P.