A small block is shot into each of the four tracks as shown below. Each of the tracks rises to the same height. The speed with which the block enters the track is the same in all cases. At the highest point of the track, the normal reaction is maximum in

Question

A small block is shot into each of the four tracks as shown below. Each of the tracks rises to the same height. The speed with which the block enters the track is the same in all cases. At the highest point of the track, the normal reaction is maximum in [2001]

Smart Achievers · Accepted Answer

(1)

According to question, the speed with which the block enters the track is the same in all the tracks and the block rises to the same height, so from the law of conservation of energy, speed of the block at the highest point will be same in all four cases.

Let the velocity at the highest point be $v$ .

$(N + m g) provides the centripetal force \frac{m v^{2}}{R} to the body$

$N + m g = \frac{m v^{2}}{R}$

$or N = \frac{m v^{2}}{R} - m g$

$R$ (the radius of curvature) in the first case is minimum.

Hence, normal reaction N will be maximum in the first case.

Solution

Q.
A small block is shot into each of the four tracks as shown below. Each of the tracks rises to the same height. The speed with which the block enters the track is the same in all cases. At the highest point of the track, the normal reaction is maximum in [2001]

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Solution

Q. A small block is shot into each of the four tracks as shown below. Each of the tracks rises to the same height. The speed with which the block enters the track is the same in all cases. At the highest point of the track, the normal reaction is maximum in [2001]

1

2

3

4

Want Us to Email you About Special Offers & Updates?

Q.
A small block is shot into each of the four tracks as shown below. Each of the tracks rises to the same height. The speed with which the block enters the track is the same in all cases. At the highest point of the track, the normal reaction is maximum in [2001]