A plane electromagnetic wave of frequency 20 MHz propagates in free space along -direction. At a particular space and time, . What is at this point? [2023]

Question

A plane electromagnetic wave of frequency 20 MHz propagates in free space along $x$ -direction. At a particular space and time, $\vec{E} = 6.6 \hat{j} V/m$ . What is $\vec{B}$ at this point? [2023]

Smart Achievers · Accepted Answer

(2)

$\hat{E} = 6.6 \hat{j}, ν = 20 MHz, \vec{c} = 3 \times 10^{8} \hat{i}$

$| \vec{B} |$ $= \frac{| \vec{E} |}{c} = 2.2 \times 10^{- 8} T$

$\hat{E} \times \hat{B} = \hat{c} \Rightarrow \hat{B} = 2.2 \times 10^{- 8} \hat{k} T$

Solution

Q.
A plane electromagnetic wave of frequency 20 MHz propagates in free space along $x$ -direction. At a particular space and time, $\vec{E} = 6.6 \hat{j} V/m$ . What is $\vec{B}$ at this point [2023]

1 $- 2.2 \times 10^{- 8} \hat{i} T$

2 $2.2 \times 10^{- 8} \hat{k} T$

3 $- 2.2 \times 10^{- 8} \hat{k} T$

4 $2.2 \times 10^{- 8} \hat{i} T$

Ans.
(2)

$\hat{E} = 6.6 \hat{j}, ν = 20 MHz, \vec{c} = 3 \times 10^{8} \hat{i}$

$| \vec{B} |$ $= \frac{| \vec{E} |}{c} = 2.2 \times 10^{- 8} T$

$\hat{E} \times \hat{B} = \hat{c} \Rightarrow \hat{B} = 2.2 \times 10^{- 8} \hat{k} T$

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Solution

Q. A plane electromagnetic wave of frequency 20 MHz propagates in free space along x-direction. At a particular space and time, E→=6.6j^ V/m. What is B→ at this point [2023]

1 -2.2×10-8 i^ T

2 2.2×10-8 k^ T

3 -2.2×10-8 k^ T

4 2.2×10-8 i^ T

Ans. (2) E^=6.6 j^, ν=20 MHz, c→=3×108 i^ |B→|=|E→|c=2.2×10-8 T E^×B^=c^ ⇒ B^=2.2×10-8 k^ T