A person of mass 50 kg stands on a weighing scale on a lift. If the lift is ascending upwards with a uniform acceleration of 9 , what would be the reading of the weighing scale?

Question

A person of mass 50 kg stands on a weighing scale on a lift. If the lift is ascending upwards with a uniform acceleration of 9 $m s^{- 2}$ , what would be the reading of the weighing scale? (Take g = 10 $m s^{- 2}$ )

Smart Achievers · Accepted Answer

(3)

The reading on the scale is a measure of the force on the floor by the person. By Newton’s third law this is equal and opposite to the normal force N on the person by the floor.

$∴$ When the lift is ascending upwards with an acceleration of 9 $m s^{- 2}$ , then

N − 50 × 10 = 50 × 9 or N = 50 × 10 + 50 × 9 = 50(10 + 9) = 950 N

$∴$ The reading of weighing machine is 95 kg.

Solution

Q.
A person of mass 50 kg stands on a weighing scale on a lift. If the lift is ascending upwards with a uniform acceleration of 9 $m s^{- 2}$ , what would be the reading of the weighing scale (Take g = 10 $m s^{- 2}$ )

1 50 kg

2 60 kg

3 95 kg

4 100 kg

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