Q.

A particle starts moving from point (2, 10, 1). Displacement for the particle is 8i^−2j^+k^. The final coordinates of the particle is

1 (10, 8, 2)  
2 (8, 10, 2)  
3 (2, 10, 8)  
4 (8, 2, 10)  

Ans.

(1)

Initial position vector of the particle, r→i=2i^+10j^+k^

Let final position vector of the particle be

r→f=xi^+yj^+zk^

∴  Displacement, Δr→=r→f-r→i

8i^-2j^+k^=xi^+yj^+zk^-(2i^+10j^+k^)

or  xi^+yj^+zk^=10i^+8j^+2k^

Hence, the final coordinates of the particle are (10, 8, 2).