Q.

A particle of mass m moves in circular orbits with potential energy V(r)=Fr, where F is a positive constant and r is its distance from the origin. Its energies are calculated using the Bohr model. If the radius of the particle's orbit is denoted by R and its speed and energy are denoted by v and E, respectively, then for the nth orbit (here h is the Planck's constant)                                [2020]

1 R∝n1/3 and v∝n2/3  
2 R∝n2/3 and v∝n1/3  
3 E=32(n2h2F24π2m)1/3  
4 E=2(n2h2F24π2m)1/3  

Ans.

(2, 3)

Given: Potential energy of the particle of mass 'm' moving in a circular orbit, V(r)=Fr

⇒F=V(r)r

Also, centripetal force,

F=mv2R                       ⋯(1)

According to Bohr's second postulate,

mvR=nh2π⇒v=nh2πmR

Putting this value of v in Eq. (1),

F=mR×n2h22π2×1m2R2⇒R=(n2h24π2mF)1/3    ∴  R∝n2/3

Now putting this value of R in  v=nh2πmR

v=nh2πm(4π2mFn2h2)1/3          ∴   v∝n1/3

Hence, option (2) is correct.

Total energy,  E=12mv2+V(r)=12mv2+FR

⇒E=12m(n2/3h2/3F2/322/3π2/3m4/3)+F(n2h24π2mF)1/3

⇒E=(n2h2F24π2m)1/3[12+1]   or,   E=32(n2h2F24π2m)1/3

Hence, option (3) is correct.