A particle of mass m = 2 kg is moving at 5 m/s in a given direction and is struck by an impulsive force F that deflects its direction of motion through 60° and doubles the magnitude of its velocity. The same impulsive force F is applied to a mass of 5m at

Question

A particle of mass m = 2 kg is moving at 5 m/s in a given direction and is struck by an impulsive force F that deflects its direction of motion through $60 °$ and doubles the magnitude of its velocity. The same impulsive force F is applied to a mass of 5m at rest. What is the resulting kinetic energy of mass 5m (in J)?

Smart Achievers · Accepted Answer

(15)

$F Δ t =$ $| Δ \vec{p} |$ $= m v \sqrt{3}$

$= 10 \sqrt{3} kg m/s$

$Now F Δ t = 5 m V_{0}$

$K = \frac{1}{2} 5 m V_{0}^{2} = 15 J$

Solution

Ans.
(15)

$F Δ t =$ $| Δ \vec{p} |$ $= m v \sqrt{3}$

$= 10 \sqrt{3} kg m/s$

$Now F Δ t = 5 m V_{0}$

$K = \frac{1}{2} 5 m V_{0}^{2} = 15 J$

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Solution

Ans. (15) FΔt=|Δp→|=mv3 =103 kg m/s Now FΔt=5mV0 K=12 5mV02=15J

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Ans.
(15)

$F Δ t =$ $| Δ \vec{p} |$ $= m v \sqrt{3}$

$= 10 \sqrt{3} kg m/s$

$Now F Δ t = 5 m V_{0}$

$K = \frac{1}{2} 5 m V_{0}^{2} = 15 J$