Q.

A particle of charge 1.6 μC and mass 16 μg is present in a strong magnetic field of 6.28 T. The particle is then fired perpendicular to magnetic field. The time required for the particle to return to original location for the first time is __________ ms. (π = 3.14)          [2025]


Ans.

(10)

Angle between v of charge and B is 90° motion will be uniform circular motion time period is given by

T=2πmqB=2π×16×109 kg1.6×106×6.28 = 0.01 seconds