Q.

A particle is moving in one dimension (along x-axis) under the action of a variable force. It's initial position was 16 m right of origin. The variation of its position (x) with time (t) is given as x=-3t3+18t2+16t, where x is in m and t in s. The velocity of the particle when its acceleration becomes zero is _____ m/s.            [2024]


Ans.

(52)        x=3t3+18t2+16t

              v=-9t2+36t+16

              a=-18t+36

              a=0 at t=2 s

              v=-9(2)2+36×2+16

              v=52m/s