A particle having electric charge and mass is accelerated by applying an electric potential of 1.21V. Wavelength of the matter wave associated with the particle is . The value of is______

Question

A particle having electric charge $3 \times 10^{- 19} C$ and mass $6 \times 10^{- 27} kg$ is accelerated by applying an electric potential of 1.21 V. Wavelength of the matter wave associated with the particle is $α \times 10^{- 12} m$ . The value of $α$ is_______.

$(Take Planck's constant = 6.6 \times 10^{- 34} J·s)$ [2026]

Smart Achievers · Accepted Answer

(10)

$λ = \frac{h}{\sqrt{2 m q V}}$

$λ = \frac{6.6 \times 10^{- 34}}{\sqrt{2 \times 18 \times 10^{- 46} \times 1.21}}$

$λ = 10^{- 11} m = 10 \times 10^{- 12} m$

$α = 10$

Solution

Ans.
(10)

$λ = \frac{h}{\sqrt{2 m q V}}$

$λ = \frac{6.6 \times 10^{- 34}}{\sqrt{2 \times 18 \times 10^{- 46} \times 1.21}}$

$λ = 10^{- 11} m = 10 \times 10^{- 12} m$

$α = 10$

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Solution

Q. A particle having electric charge 3×10-19 C and mass 6×10-27 kg is accelerated by applying an electric potential of 1.21 V. Wavelength of the matter wave associated with the particle is α×10-12 m. The value of α is_______. (Take Planck's constant =6.6×10-34 J·s) [2026]

Ans. (10) λ=h2mqV λ=6.6×10-342×18×10-46×1.21 λ=10-11 m=10×10-12 m α=10

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Ans.
(10)

$λ = \frac{h}{\sqrt{2 m q V}}$

$λ = \frac{6.6 \times 10^{- 34}}{\sqrt{2 \times 18 \times 10^{- 46} \times 1.21}}$

$λ = 10^{- 11} m = 10 \times 10^{- 12} m$

$α = 10$