A particle executes simple harmonic motion between and The time taken for it to go from 0 to is and to go from to is . Then [2001]

Question

A particle executes simple harmonic motion between $x = - A$ and $x = + A .$ The time taken for it to go from 0 to $\frac{A}{2}$ is $T_{1}$ and to go from $\frac{A}{2}$ to $A$ is $T_{2}$ . Then [2001]

Smart Achievers · Accepted Answer

(1)

In SHM, velocity of particles goes on decreasing from maximum value to zero as the particles travel from mean position to extreme position.

Therefore if the time taken for the body to go from $O$ to $\frac{A}{2}$ is $T_{1}$ and to go from $\frac{A}{2}$ to $A$ is $\frac{A}{2}$ then obviously $A$

Solution

Q.
A particle executes simple harmonic motion between $x = - A$ and $x = + A .$ The time taken for it to go from 0 to $\frac{A}{2}$ is $T_{1}$ and to go from $\frac{A}{2}$ to $A$ is $T_{2}$ . Then [2001]

1 $T_{1} < T_{2}$

2 $T_{1} > T_{2}$

3 $T_{1} = T_{2}$

4 $T_{1} = 2 T_{2}$

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Solution

Q. A particle executes simple harmonic motion between x=-A and x=+A. The time taken for it to go from 0 to A2 is T1 and to go from A2 to A is T2. Then [2001]

1 T1<T2

2 T1>T2

3 T1=T2

4 T1=2T2