A parallel plate capacitor has charge . A dielectric slab is inserted between the plates and almost fills the space between the plates. If the induced charge on one face of the slab is then the dielectric constant of the slab is __________ [2025]

Question

A parallel plate capacitor has charge $5 \times 10^{- 6} C$ . A dielectric slab is inserted between the plates and almost fills the space between the plates. If the induced charge on one face of the slab is $4 \times 10^{- 6} C$ then the dielectric constant of the slab is __________ [2025]

Smart Achievers · Accepted Answer

(5)

$E_{net} = E_{0} - E_{i n}$

$E_{in} = E_{0} (1 - \frac{1}{k})$

$Q_{in} = Q_{0} (1 - \frac{1}{k})$

$4 \times 10^{- 6} = 5 \times 10^{- 6} (1 - \frac{1}{k}) \Rightarrow k = 5$

Solution

Q.
A parallel plate capacitor has charge $5 \times 10^{- 6} C$ . A dielectric slab is inserted between the plates and almost fills the space between the plates. If the induced charge on one face of the slab is $4 \times 10^{- 6} C$ then the dielectric constant of the slab is __________ [2025]

Ans.
(5)

$E_{net} = E_{0} - E_{i n}$

$E_{in} = E_{0} (1 - \frac{1}{k})$

$Q_{in} = Q_{0} (1 - \frac{1}{k})$

$4 \times 10^{- 6} = 5 \times 10^{- 6} (1 - \frac{1}{k}) \Rightarrow k = 5$

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Solution

Q. A parallel plate capacitor has charge 5×10–6C. A dielectric slab is inserted between the plates and almost fills the space between the plates. If the induced charge on one face of the slab is 4×10–6C then the dielectric constant of the slab is __________ [2025]

Ans. (5) Enet=E0–Ein Ein=E0(1–1k) Qin=Q0(1–1k) 4×10–6=5×10–6(1–1k) ⇒ k=5

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Q.
A parallel plate capacitor has charge $5 \times 10^{- 6} C$ . A dielectric slab is inserted between the plates and almost fills the space between the plates. If the induced charge on one face of the slab is $4 \times 10^{- 6} C$ then the dielectric constant of the slab is __________ [2025]

Ans.
(5)

$E_{net} = E_{0} - E_{i n}$

$E_{in} = E_{0} (1 - \frac{1}{k})$

$Q_{in} = Q_{0} (1 - \frac{1}{k})$

$4 \times 10^{- 6} = 5 \times 10^{- 6} (1 - \frac{1}{k}) \Rightarrow k = 5$