A mixture of carbon dioxide and oxygen has volume 8310 , temperature 300 K, pressure 100 kPa and mass 13.2 g

Question

A mixture of carbon dioxide and oxygen has volume 8310 ${cm}^{3}$ , temperature 300 K, pressure 100 kPa and mass 13.2 g. The number of moles of carbon dioxide and oxygen gases in the mixture respectively are ______.

(Assume both carbon dioxide and oxygen gases behave like ideal gases) [R = 8.31 J/mol.K] [2026]

Smart Achievers · Accepted Answer

(3)

$Total number of moles in the mixture$

$(n_{1} + n_{2}) = \frac{P V}{R T} = \frac{10^{5} \times 8.31 \times 10^{- 3}}{8.31 \times 300} = \frac{1}{3} mole \approx 0.333 mole$

$Mole equation: n_{1} + n_{2} = \frac{1}{3} \approx 0.333 mole$ $. . . (i)$

$Mass equation: 44 n_{1} + 32 n_{2} = 13.2$ $. . . (i i)$

$({where 44 and 32 are the molar masses of CO}_{2} {and O}_{2} respectively)$

$On solving eq. (i) and eq. (ii)$

$44 n_{1} + 32 (0.333 - n_{1}) = 13.2$

$44 n_{1} + 10.667 - 32 n_{1} = 13.2$

$∵$ $12 n_{1} = 2.533$

$n_{1} \approx 0.211 mol$

$then, calculate n_{2}$

$n_{2} = 0.333 - 0.211$

$n_{2} = 0.122 mol$

Solution

1 0.15 and 0.18

2 0.25 and 0.08

3 0.21 and 0.12

4 0.13 and 0.20

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