A mass of 1 kg is suspended by means of a thread. The system is (i) lifted up with an acceleration of 4.9 (ii) lowered with an acceleration of 4.9 . The ratio of tension in the first and second case is

Question

A mass of 1 kg is suspended by means of a thread. The system is (i) lifted up with an acceleration of 4.9 $m s^{- 2}$ (ii) lowered with an acceleration of 4.9 $m s^{- 2}$ . The ratio of tension in the first and second case is

Smart Achievers · Accepted Answer

(1)

Case I:

Using Newton's second law of motion,

$T_{1} - m g = m a$

$T_{1} = m (g + a)$ $\dots (i)$

Case II:

Using Newton's second law of motion,

$m g - T_{2} = m a$

$T_{2} = m (g - a)$ $\dots (i i)$

From eqn. (i) and (ii),

$\frac{T_{1}}{T_{2}} = \frac{g + a}{g - a} = \frac{9.8 + 4.9}{9.8 - 4.9} = \frac{3}{1}$

Solution

Q.
A mass of 1 kg is suspended by means of a thread. The system is (i) lifted up with an acceleration of 4.9 $m s^{- 2}$ (ii) lowered with an acceleration of 4.9 $m s^{- 2}$ . The ratio of tension in the first and second case is

1 3 : 1

2 1 : 2

3 1 : 3

4 2 : 1

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