A liquid mixture contains 10 moles of A and 10 moles of B . The vapour pressure over the liquid mixture is 160 mmHg. Which is the correct statement?

Question

A liquid mixture contains 10 moles of A $(P_{A}^{o} = 200 mmHg)$ and 10 moles of B $(P_{B}^{o} = 100 mmHg)$ . The vapour pressure over the liquid mixture is 160 mmHg. Which is the correct statement?

Smart Achievers · Accepted Answer

(4)

$P_{solution} = 160$

Solution has positive deviation from Raoult's law.

$P_{total} = 200 \times 0.5 + 100 \times 0.5 = 150$

$Δ G_{mix} < 0, Δ V_{mix} > 0, Δ H_{mix} > 0$

$Δ S_{surr} < 0$

Solution

Q.
A liquid mixture contains 10 moles of A $(P_{A}^{o} = 200 mmHg)$ and 10 moles of B $(P_{B}^{o} = 100 mmHg)$ . The vapour pressure over the liquid mixture is 160 mmHg. Which is the correct statement

1 $Δ G_{mix} = + v e$

2 $Δ V_{mix} = - v e$

3 $Δ S_{surrounding} = + v e$

4 $Δ S_{surrounding} = - v e$

Ans.
(4)

$P_{solution} = 160$

Solution has positive deviation from Raoult's law.

$P_{total} = 200 \times 0.5 + 100 \times 0.5 = 150$

$Δ G_{mix} < 0, Δ V_{mix} > 0, Δ H_{mix} > 0$

$Δ S_{surr} < 0$

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Solution

Q. A liquid mixture contains 10 moles of A (PAo=200 mmHg) and 10 moles of B (PBo=100 mmHg). The vapour pressure over the liquid mixture is 160 mmHg. Which is the correct statement

1 ΔGmix=+ve

2 ΔVmix=-ve

3 ΔSsurrounding=+ve

4 ΔSsurrounding=-ve

Ans. (4) Psolution=160 Solution has positive deviation from Raoult's law. Ptotal=200×0.5+100×0.5=150 ΔGmix<0, ΔVmix>0, ΔHmix>0 ΔSsurr<0