Q.

A hydrogen atom in its ground state is irradiated by light of wavelength 970 Å. Taking hce=1.237×10-6 eV m and the ground state energy of hydrogen atom as -13.6 eV, the number of lines present in the emission spectrum is                      [2016]


Ans.

(6)

Energy of incident light,

E=hcλ=1.237×10-6970×10-10 eV=12.75 eV

∴  The energy of electron after absorbing this photon =-13.6+12.75=-0.85 eV

Let the electron jump to the nth state after excitation.

∴   -13.6n2=-0.85     ∴ n=4

∴  Total number of spectral lines =n(n-1)2=4(4-1)2=6