A function is defined on as where denotes greatest integer , number of points where is not differentiable in is

Question

A function $f$ is defined on $[- 3, 3]$ as $f (x) =$ ${\begin{matrix} \min {| x |, 2 - x^{2}}, & - 2 \leq x \leq 2 \\ [| x |], & 2 < | x | \leq 3 \end{matrix}$ where $[x]$ denotes greatest integer $\leq x$ , number of points where $f$ is not differentiable in $(- 3, 3)$ is

Smart Achievers · Accepted Answer

(3)

It is non diff at 5 point -2, -1, 0, 1, 2

Solution

Q.
A function $f$ is defined on $[- 3, 3]$ as $f (x) =$ ${\begin{matrix} \min {| x |, 2 - x^{2}}, & - 2 \leq x \leq 2 \\ [| x |], & 2 < | x | \leq 3 \end{matrix}$ where $[x]$ denotes greatest integer $\leq x$ , number of points where $f$ is not differentiable in $(- 3, 3)$ is

1 3

2 4

3 5

4 2

Ans.
(3)

It is non diff at 5 point -2, -1, 0, 1, 2

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Solution

Q. A function f is defined on [-3,3] as f(x)={min{|x|, 2-x2},-2≤x≤2[|x|],2<|x|≤3 where [x] denotes greatest integer ≤x, number of points where f is not differentiable in (-3,3) is

1 3

2 4

3 5

4 2

Ans. (3) It is non diff at 5 point -2, -1, 0, 1, 2

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Q.
A function $f$ is defined on $[- 3, 3]$ as $f (x) =$ ${\begin{matrix} \min {| x |, 2 - x^{2}}, & - 2 \leq x \leq 2 \\ [| x |], & 2 < | x | \leq 3 \end{matrix}$ where $[x]$ denotes greatest integer $\leq x$ , number of points where $f$ is not differentiable in $(- 3, 3)$ is

Ans.
(3)

It is non diff at 5 point -2, -1, 0, 1, 2