A force F=(5+3y2) acts on a particle in the y-direction, where F is newton and y is in meter. The work done by the force during a displacement from y = 2 m to y = 5 m is _______ J. [2023]
(132)
F=5+3y2
W=∫25(5+3y2)dy=[5y+3y33]25=132 J