Q.

A disc revolves with a speed 3313 rev/min, and has a radius of 15 cm. Two coins A and B are placed at 4 cm and 14 cm away from the centre of the disc. If the coefficient of friction between the coins and the disc is 0.15, which of the coins will revolve with the disc

1 A  
2 B  
3 Both A and B  
4 Neither A nor B  

Ans.

(1)

Here, μ=0.15,

ν=3313 rpm=1003 rpm=1003×60 rps=59 rps

∴  ω=2πν=2×227×59=22063 rad s-1

The coin will revolve with the disc, if the force of friction is enough to provide the necessary centripetal force.

i.e.,  mv2r≤μmg

As v=rω,

∴  mω2r≤μmg

For the given μ and ω, the condition is r≤μgω2        ⋯(i)

As  μgω2=0.15×10(22063)2≈12 cm

For coin A, r=4 cm.

The above condition is satisfied, therefore coin A will revolve with the disc.

For coin B, r=14 cm.

The above condition is not satisfied, therefore coin B will not revolve with the disc.

Note: We have nothing to do with the radius of the disc.