A cylinder of height 20 m is completely filled with water

Question

A cylinder of height 20 m is completely filled with water. The velocity of efflux of water $({in ms}^{- 1})$ through a small hole on the side wall of the cylinder near its bottom is $(take g = 10 {m/s}^{2})$

Smart Achievers · Accepted Answer

(20)

$Given, Height of cylinder, h = 20 cm$

$Acceleration due to gravity, g = 10 {ms}^{- 2}$

$Velocity of efflux v = \sqrt{2 g h}$

$Where h is the height of the free surface of liquid from the hole$

$v = \sqrt{2 \times 10 \times 20} = 20 m/s$

Solution

Q.
A cylinder of height 20 m is completely filled with water. The velocity of efflux of water $({in ms}^{- 1})$ through a small hole on the side wall of the cylinder near its bottom is $(take g = 10 {m/s}^{2})$

Ans.
(20)

$Given, Height of cylinder, h = 20 cm$

$Acceleration due to gravity, g = 10 {ms}^{- 2}$

$Velocity of efflux v = \sqrt{2 g h}$

$Where h is the height of the free surface of liquid from the hole$

$v = \sqrt{2 \times 10 \times 20} = 20 m/s$

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Solution

Q. A cylinder of height 20 m is completely filled with water. The velocity of efflux of water (in ms-1) through a small hole on the side wall of the cylinder near its bottom is (take g=10 m/s2)

Ans. (20) Given, Height of cylinder, h=20 cm Acceleration due to gravity, g=10 ms-2 Velocity of efflux v=2gh Where h is the height of the free surface of liquid from the hole v=2×10×20=20 m/s

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Q.
A cylinder of height 20 m is completely filled with water. The velocity of efflux of water $({in ms}^{- 1})$ through a small hole on the side wall of the cylinder near its bottom is $(take g = 10 {m/s}^{2})$

Ans.
(20)

$Given, Height of cylinder, h = 20 cm$

$Acceleration due to gravity, g = 10 {ms}^{- 2}$

$Velocity of efflux v = \sqrt{2 g h}$

$Where h is the height of the free surface of liquid from the hole$

$v = \sqrt{2 \times 10 \times 20} = 20 m/s$