A cylinder is rolling down on an inclined plane of inclination 60°. Its acceleration during rolling down will be , where

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Solution

Q.
A cylinder is rolling down on an inclined plane of inclination 60°. Its acceleration during rolling down will be $\frac{x}{\sqrt{3}} m / s^{2}$ , where $x$ = _____. (use $g = 10 m / s^{2}$ ). [2024]

Ans.
(10)

For rolling motion, $a = \frac{g \sin θ}{1 + \frac{I_{c m}}{M R^{2}}}$

$a = \frac{g \sin θ}{1 + \frac{1}{2}} = \frac{2 \times 10 \times \frac{\sqrt{3}}{2}}{3} = \frac{10}{\sqrt{3}} {m/s}^{2}$

Therefore $x = 10$

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