A cube has side length 5 cm and modulus of rigidity . The displacement produced by a force of 10 N in

Question

A cube has side length 5 cm and modulus of rigidity $10^{5} {N/m}^{2}$ . The displacement produced by a force of 10 N in the upper face of cube is ______ mm. [2026]

Smart Achievers · Accepted Answer

(2)

$η = \frac{F / A}{ϕ} = \frac{F h}{A x}$

$x = \frac{F h}{A η} = \frac{10 \times 5 \times 10^{- 2}}{25 \times 10^{- 4} \times 10^{5}} = \frac{1}{500} m$

$∴$ $x = 2 mm$

Solution

Q.
A cube has side length 5 cm and modulus of rigidity $10^{5} {N/m}^{2}$ . The displacement produced by a force of 10 N in the upper face of cube is ______ mm. [2026]

Ans.
(2)

$η = \frac{F / A}{ϕ} = \frac{F h}{A x}$

$x = \frac{F h}{A η} = \frac{10 \times 5 \times 10^{- 2}}{25 \times 10^{- 4} \times 10^{5}} = \frac{1}{500} m$

$∴$ $x = 2 mm$

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Solution

Q. A cube has side length 5 cm and modulus of rigidity 105 N/m2. The displacement produced by a force of 10 N in the upper face of cube is ______ mm. [2026]

Ans. (2) η=F/Aϕ=FhAx x=FhAη=10×5×10-225×10-4×105=1500 m ∴ x=2 mm

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Q.
A cube has side length 5 cm and modulus of rigidity $10^{5} {N/m}^{2}$ . The displacement produced by a force of 10 N in the upper face of cube is ______ mm. [2026]

Ans.
(2)

$η = \frac{F / A}{ϕ} = \frac{F h}{A x}$

$x = \frac{F h}{A η} = \frac{10 \times 5 \times 10^{- 2}}{25 \times 10^{- 4} \times 10^{5}} = \frac{1}{500} m$

$∴$ $x = 2 mm$