A copper wire of radius 1 mm contains free electrons per cubic metre. The drift velocity for free electrons when 10 A current flows through the wire will be (Given, charge on electron C): [2023]

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Q.
A copper wire of radius 1 mm contains $10^{22}$ free electrons per cubic metre. The drift velocity for free electrons when 10 A current flows through the wire will be (Given, charge on electron $= 1.6 \times 10^{- 19}$ C): [2023]

1 $\frac{6.25 \times 10^{4}}{π}$ ${ms}^{- 1}$

2 $\frac{6.25}{π} \times 10^{3}$ ${ms}^{- 1}$

3 $\frac{6.25}{π}$ ${ms}^{- 1}$

4 $\frac{6.25 \times 10^{5}}{π}$ ${ms}^{- 1}$

Ans.
(2)

The relation between current and drift velocity is given as $I = n_{e} A v_{d}$

Rearranging and substituting the values,

$v_{d} = \frac{I}{n e A} = \frac{10}{10^{22} \times 1.6 \times 10^{- 19} \times π \times 10^{- 6}}; v_{d} = \frac{6.25}{π} \times 10^{3}$ $m / s$

Solution

Q.
A copper wire of radius 1 mm contains $10^{22}$ free electrons per cubic metre. The drift velocity for free electrons when 10 A current flows through the wire will be (Given, charge on electron $= 1.6 \times 10^{- 19}$ C): [2023]

1 $\frac{6.25 \times 10^{4}}{π}$ ${ms}^{- 1}$

2 $\frac{6.25}{π} \times 10^{3}$ ${ms}^{- 1}$

3 $\frac{6.25}{π}$ ${ms}^{- 1}$

4 $\frac{6.25 \times 10^{5}}{π}$ ${ms}^{- 1}$

Ans.
(2)

The relation between current and drift velocity is given as $I = n_{e} A v_{d}$

Rearranging and substituting the values,

$v_{d} = \frac{I}{n e A} = \frac{10}{10^{22} \times 1.6 \times 10^{- 19} \times π \times 10^{- 6}}; v_{d} = \frac{6.25}{π} \times 10^{3}$ $m / s$

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Solution

Q. A copper wire of radius 1 mm contains 1022 free electrons per cubic metre. The drift velocity for free electrons when 10 A current flows through the wire will be (Given, charge on electron =1.6×10-19C): [2023]

1 6.25×104π ms-1

2 6.25π×103 ms-1

3 6.25π ms-1

4 6.25×105π ms-1

Ans. (2) The relation between current and drift velocity is given as I=neAvd Rearranging and substituting the values, vd=IneA=101022×1.6×10-19×π×10-6 ; vd=6.25π×103 m/s

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Q.
A copper wire of radius 1 mm contains $10^{22}$ free electrons per cubic metre. The drift velocity for free electrons when 10 A current flows through the wire will be (Given, charge on electron $= 1.6 \times 10^{- 19}$ C): [2023]

1 $\frac{6.25 \times 10^{4}}{π}$ ${ms}^{- 1}$

2 $\frac{6.25}{π} \times 10^{3}$ ${ms}^{- 1}$

3 $\frac{6.25}{π}$ ${ms}^{- 1}$

4 $\frac{6.25 \times 10^{5}}{π}$ ${ms}^{- 1}$

Ans.
(2)

The relation between current and drift velocity is given as $I = n_{e} A v_{d}$

Rearranging and substituting the values,

$v_{d} = \frac{I}{n e A} = \frac{10}{10^{22} \times 1.6 \times 10^{- 19} \times π \times 10^{- 6}}; v_{d} = \frac{6.25}{π} \times 10^{3}$ $m / s$