A circuit is connected as shown in the figure with the switch $S$ open. When the switch is closed, the total amount of charge that flows from Y to X is [2007]

Question

Smart Achievers · Accepted Answer

(3)

When the switch $S$ is open, total charge $Q_{1} + Q_{2} = 0$

$C V_{1} + C_{2} V_{2} = 3 \times 6 + (- 6 \times 3) = 0 .$ When the switch is closed and steady state is reached, the current $I$ coming from the battery is $9 = I (3 + 6)$ $\Rightarrow I = 1 A$ $(∵ V = I R)$

$∴$ $Potential difference across 3 Ω resistance = 3 V$

$∴$ $Potential difference across 6 Ω resistance = 6 V$

$∴$ $p.d. across 3 μ F capacitor = 3 V$ $and p.d. across 6 μ F capacitor = 6 V$

$∴$ $Charge on 3 μ F capacitor, Q_{1} = 3 \times 3 = 9 μ C$

$Charge on 6 μ F capacitor, Q_{2} = 6 \times 6 = 36 μ C$

$∴$ $Charge flows from y to x = 36 - 9 = 27 μ C$

Solution

Q.
A circuit is connected as shown in the figure with the switch $S$ open. When the switch is closed, the total amount of charge that flows from Y to X is [2007]

1 $0$

2 $54 μ C$

3 $27 μ C$

4 $81 μ C$

Want Us to Email you About Special Offers & Updates?

Solution

Q. A circuit is connected as shown in the figure with the switch S open. When the switch is closed, the total amount of charge that flows from Y to X is [2007]

1 0

2 54 μC

3 27 μC