A charge particle of accelerated by a potential difference of 100 V enters a region of uniform magnetic field of magnitude 4 mT at right angle to the direction of field. The charge particle completes a semicircle of radius 3 cm inside magnetic field. The

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Solution

Q.
A charge particle of $2 μ C$ accelerated by a potential difference of 100 V enters a region of uniform magnetic field of magnitude 4 mT at right angle to the direction of field. The charge particle completes a semicircle of radius 3 cm inside magnetic field. The mass of the charge particle is ________ $\times 10^{- 18} kg$ . [2023]

Ans.
(144)

$r = \frac{m v}{q B} = \frac{\sqrt{2 k m}}{q B}$

$m = \frac{r^{2} q^{2} B^{2}}{2 k}$

$m = \frac{\frac{1}{100} \times \frac{3}{100} \times 2 \times 2 \times 4 \times 10^{- 3} \times 4 \times 10^{- 3} \times 10^{- 12}}{2 \times (100) \times 10^{- 6}}$

$= 144 \times 10^{- 18} kg$

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