A charge is placed at the centre of a cube. The flux coming out from any one of its faces will be (in SI unit) [2023]

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Q.
A charge $Q$ $μ C$ is placed at the centre of a cube. The flux coming out from any one of its faces will be (in SI unit) [2023]

1 $\frac{Q}{ε_{0}} \times 10^{- 6}$

2 $\frac{2 Q}{3 ε_{0}} \times 10^{- 3}$

3 $\frac{Q}{6 ε_{0}} \times 10^{- 3}$

4 $\frac{Q}{6 ε_{0}} \times 10^{- 6}$

Ans.
(4)

Total flux from any closed surface is $\frac{1}{ε_{0}}$ times net charge enclosed. So flux from any one surface of cube is $\frac{1}{6 ε_{0}}$ times total charge enclosed.

$= \frac{Q μ C}{6 ε_{0}} = \frac{Q \times 10^{- 6}}{6 ε_{0}}$

Solution

Q.
A charge $Q$ $μ C$ is placed at the centre of a cube. The flux coming out from any one of its faces will be (in SI unit) [2023]

1 $\frac{Q}{ε_{0}} \times 10^{- 6}$

2 $\frac{2 Q}{3 ε_{0}} \times 10^{- 3}$

3 $\frac{Q}{6 ε_{0}} \times 10^{- 3}$

4 $\frac{Q}{6 ε_{0}} \times 10^{- 6}$

Ans.
(4)

Total flux from any closed surface is $\frac{1}{ε_{0}}$ times net charge enclosed. So flux from any one surface of cube is $\frac{1}{6 ε_{0}}$ times total charge enclosed.

$= \frac{Q μ C}{6 ε_{0}} = \frac{Q \times 10^{- 6}}{6 ε_{0}}$

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Solution

Q. A charge Q μC is placed at the centre of a cube. The flux coming out from any one of its faces will be (in SI unit) [2023]

1 Qε0×10-6

2 2Q3ε0×10-3

3 Q6ε0×10-3

4 Q6ε0×10-6

Ans. (4) Total flux from any closed surface is 1ε0 times net charge enclosed. So flux from any one surface of cube is 16ε0 times total charge enclosed. =QμC6ε0=Q×10-66ε0

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Q.
A charge $Q$ $μ C$ is placed at the centre of a cube. The flux coming out from any one of its faces will be (in SI unit) [2023]

1 $\frac{Q}{ε_{0}} \times 10^{- 6}$

2 $\frac{2 Q}{3 ε_{0}} \times 10^{- 3}$

3 $\frac{Q}{6 ε_{0}} \times 10^{- 3}$

4 $\frac{Q}{6 ε_{0}} \times 10^{- 6}$

Ans.
(4)

Total flux from any closed surface is $\frac{1}{ε_{0}}$ times net charge enclosed. So flux from any one surface of cube is $\frac{1}{6 ε_{0}}$ times total charge enclosed.

$= \frac{Q μ C}{6 ε_{0}} = \frac{Q \times 10^{- 6}}{6 ε_{0}}$