A cell of emf 90 V is connected across series combination of two resistors each of 100 resistance. A voltmeter of resistance 400 is used to measure the potential difference across each resistor. The reading of the voltmeter will be [2023]

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Solution

Q.
A cell of emf 90 V is connected across series combination of two resistors each of 100 $Ω$ resistance. A voltmeter of resistance 400 $Ω$ is used to measure the potential difference across each resistor. The reading of the voltmeter will be [2023]

1 45 V

2 40 V

3 80 V

4 90 V

Ans.
(2)

$R_{eq} = \frac{400 \times 100}{500} + 100 = 180 Ω$

$i = \frac{90}{180} = \frac{1}{2} A$

$Reading = \frac{1}{2} \times \frac{400}{500} \times 100 = 40 V$

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