A capacitor of capacitance 100 is charged to a potential of 12 V and connected to 6.4 mH inductor to produce oscillations

Question

A capacitor of capacitance 100 $μF$ is charged to a potential of 12 V and connected to 6.4 mH inductor to produce oscillations. The maximum current in the circuit would be:

Smart Achievers · Accepted Answer

(2)

$For LC oscillation,$

$Maximum current, I = Q_{0} ω = \frac{C V}{\sqrt{L C}} = V \sqrt{\frac{C}{L}}$

$[∵ ω = \frac{1}{\sqrt{L C}} & Q_{0} = C V]$

$= 12 \sqrt{\frac{100 \times 10^{- 6}}{6.4 \times 10^{- 3}}} = 1.5 A$

Solution

Q.
A capacitor of capacitance 100 $μF$ is charged to a potential of 12 V and connected to 6.4 mH inductor to produce oscillations. The maximum current in the circuit would be:

1 1.2 A

2 1.5 A

3 3.2 A

4 2.0 A

Ans.
(2)

$For LC oscillation,$

$Maximum current, I = Q_{0} ω = \frac{C V}{\sqrt{L C}} = V \sqrt{\frac{C}{L}}$

$[∵ ω = \frac{1}{\sqrt{L C}} & Q_{0} = C V]$

$= 12 \sqrt{\frac{100 \times 10^{- 6}}{6.4 \times 10^{- 3}}} = 1.5 A$

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