Q.

A body of mass 1 kg begins to move under the action of a time dependent force F→=(ti^+3t2j^)N. where i^ and j^ are the unit vectors along x and y axis. The power developed by the above force, at the time t=2 s will be _______ W.          [2023]


Ans.

(100)

F→=ti^+3t2j^

mdv→dt=ti^+3t2j^

m=1 kg, ∫0vdv=∫0ttdti^+∫0t3t2dtj^

v→=t22i^+t3j^

Power=F→·v→=t32+3t5

At t=2, Power=82+3×32=100