Q.

A body of mass 1 kg begins to move under the action of a time dependent force F→=(2t i^+3t2 j^)N, where i^ and j^ are unit vectors along x and y axis. What power will be developed by the force at the time t                [2016]

1 (2t3+3t4)W  
2 (2t3+3t5)W  
3 (2t2+3t3)W  
4 (2t2+4t4)W  

Ans.

(2)

Here, F→=(2ti^+3t2j^)N,  m=1kg

Acceleration of the body, a→=F→m=(2ti^+3t2j^)N1kg

Velocity of the body at time t,

         v→=∫a→dt=∫(2ti^+3t2j^) dt=t2i^+t3j^ ms-1

∴ Power developed by the force at time t,

      P=F→·v→=(2ti^+3t2j^)·(t2i^+t3j^)W=(2t3+3t5)W